There is a contest being held at Company A. Company A employs forty people. The first 3 employees to correctly complete a riddle each receives an extra vacation day that year. What is the probability that those first 3 employees are in the order of Jack, Bill, and John?

Answer:The probability that those first 3 employees are in the order of Jack, Bill, and John is [tex]\frac{1}{59280}[/tex]Step-by-step explanation:Consider the provided information.Company A employs forty people. We need to find the probability that those first 3 employees are in the order of Jack, Bill, and John?First find the total number of ways;We have 40 employees out of which we need to select only 3.This can be written as: [tex]40\times 39 \times 38=59280[/tex]The number of ways of selecting jack, bill and john in the same order = 1[tex]Probability=\frac{\text{Favorable outcomes}}{\text{Total number of outcomes}}[/tex][tex]Probability=\frac{1}{59280}[/tex]Therefore, the probability that those first 3 employees are in the order of Jack, Bill, and John is [tex]\frac{1}{59280}[/tex].